Find the measures of the angles if a pair of interior angles on the same side of the transversal are represented by (5x-32)degrees and (x + 8)degrees.
and
Find the measures of the angles if a pair of interior angles on the same side of the transversal have measures such that one angle is 4 times the measure of the other.
2007-01-31 10:06:25 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1. (5x-32)+(x+8)=180
6x-24=180
6x=204x
x=34
Therefore, one angle is 138 and the other is 42.
2. y=4x
y+x=180
5x=180
x=36=one angle and the other is 144.
2007-01-31 10:19:15 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
When interior angles on the same side of the transversal are added, they equal 180 degrees. So, you could say that 5x-32 + x +8 = 180.
6x -24=180
6x = 204
x = 34
Your first angle was 5x - 32. When you plug in x, you get 5(34)-32. Simplified, that's 138 degrees.
You know that your second angle is x + 8. When you plug in x and simplify, you get 42 degrees.
Again, the angles added together equal 180 degrees. If you call one angle x, the other would be 4x (because it's 4 times the measure of the first angle).
Your equation now is x + 4x = 180.
Simplified, that's 5x=180
Solved, that's x = 36 degrees
Your fisrt angle is 36 degrees, and your second angle is 144 degrees.
2007-01-31 18:19:41 · answer #2 · answered by mkn 2 · 0⤊ 0⤋
If you gave me a picture, I could do it ASAP, but I need to visualize things to solve them, thats just the way my brain works.
2007-01-31 18:13:08 · answer #3 · answered by Twenty0ne 2 · 0⤊ 0⤋
sorry that one has me stumpped
2007-01-31 18:10:32 · answer #4 · answered by Anonymous · 0⤊ 0⤋