2007-01-31 10:03:20 · 6 answers · asked by Car 1 in Science & Mathematics ➔ Mathematics
x^2+6x+41=0
Use quadratic formula
x = [-6 +/- sqrt(36-164)]/2
x = [-6 +/- sqrt(-128)]/2
x = [-6 +/- 8*sqrt(2)i]/2
x = -3 +/- i4sqrt(2)
x = -3 + i4sqrt(2) and
x = -3 - i4sqrt(2)
The roots are imaginary which means the graph of the function lies totally above the x-axis and never crosses it to give real soutions. This doesn't mean your equation cannot be solved as the above have indicated.
2007-01-31 10:24:49 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
This is a ringer. There is no set of numbers that will multiply out to 41 and add up to 6. Are you sure there wasn't an error in copying?
2007-01-31 18:18:55 · answer #2 · answered by obelix 6 · 0⤊ 0⤋
x^2+6x=-41
2007-01-31 18:07:13 · answer #3 · answered by ~Zaiyonna's Mommy~ 3 · 0⤊ 1⤋
thats unfactorable
there arent any factors of 41 besides 1 & 41 so it cant be broken up into to binomials and then used w/ the zero product property
2007-01-31 18:10:12 · answer #4 · answered by inkí 2 · 0⤊ 1⤋
There is no solution, because if you do the quadratic formula, you cannot find the square root of a negative number.
2007-01-31 18:16:48 · answer #5 · answered by Grace 2 · 0⤊ 0⤋
not factorable/ no solution
2007-01-31 18:08:30 · answer #6 · answered by lizbiz707 3 · 0⤊ 1⤋