I need help to the find the molarity (M) of an HCl solution made from diluting 9.0 mL of 8.0 M HCl to a new volume of 50.0 mL. If anyone could help, I would really appreciated it. Thanks in advance.
2007-01-31 09:58:05 · 4 answers · asked by ash 1 in Science & Mathematics ➔ Chemistry
M1V1 = M2V2
M1 = 8.0 M
V1 = 9.0 ml
V2 = 50 ml
M2 = ???
2007-01-31 10:03:20 · answer #1 · answered by Dr W 7 · 1⤊ 0⤋
First the 9.0 and 50.0 mL have to be turned into liters.
Which would be .0009 L and .0050L. And assuming that the amount of solute is the same in both cases. I would fit the known numbers into the molarity equation.
Molarity=Amount of solute (mol) / volume of solution (L)
8.0 mol/L (example amount)= ? mol/ .0009L
Useing that equation you solve for the amount of solute.
When you find that amount of moles, fit it in a new equation, solving for molarity. Which would be that original amount of solute, you have to calculate it, divided by .0050 L. The molarity shound be lower, I believe.
P.S: Hope this helps.
P.P.S: / stands for divided by.
2007-01-31 10:20:55 · answer #2 · answered by paris_kitties_pink 2 · 0⤊ 1⤋
use M1V1=M2V2
so 9*8/50
=1.44
2007-01-31 10:29:42 · answer #3 · answered by jj 2 · 1⤊ 0⤋
1.44M; don't forget that M is in units of mol/L
2007-01-31 10:22:11 · answer #4 · answered by joythang40 1 · 0⤊ 1⤋