2007-01-31 09:44:22 · 7 answers · asked by Jeffrey & ??? 1 in Science & Mathematics ➔ Mathematics
7 + q = 30
q = 23
2007-01-31 09:49:39 · answer #1 · answered by Crap_At_Maths 2 · 0⤊ 0⤋
10 + q - 3 = 6*5
we move the terms around on the left and get
q + 7 = 30
we subtract 7 from both sides
q = 23.
to check we substitute 23 and see
10 + 23 - 3 = 6*5
33 - 3 = 30
30 = 30
perfect!
2007-01-31 17:52:14 · answer #2 · answered by ? 4 · 0⤊ 0⤋
10+q-3=6*5
You can re-write as:
10-3+q=6*5 - 10-3=7 & 6*5=30 which gives you:
7+q=30 subtract 7 from both sides of = sign
q=23
PROOF:
10+23-3=6*5 - 10+23=33 & 6*5=30
33-3=30
30=30
2007-01-31 17:59:42 · answer #3 · answered by grepht 1 · 0⤊ 0⤋
10 + q - 3 = 30
7 + q = 30
q = 23
2007-01-31 17:50:10 · answer #4 · answered by Como 7 · 0⤊ 0⤋
10+q-3=6*5
multiply 6*5
10+q-3=30
add 3 to the 30
10+q=33
now subtract 10 frm both sides
q=23
2007-01-31 17:54:23 · answer #5 · answered by Anonymous · 0⤊ 0⤋
First, you add the three to both sides, giving you
10+q=6*5+3
Then, you subtract the 10 from both sides.
q=6*5+3-10
Multiply 6*5
q=30+3-10
Add 3
q=33-10
Subtract 10
q=23.
2007-01-31 17:50:39 · answer #6 · answered by Fireball 2 · 0⤊ 0⤋
10+q-3=6*5
7+q=30
-7 -7
q=23
check:
10+23-3=6*5
33-3=6*5
30=30
correct answer
2007-01-31 17:52:35 · answer #7 · answered by jasam4lyfe 2 · 0⤊ 0⤋