any help would be grreat!!! thanks!
2007-01-31 09:42:27 · 4 answers · asked by Jen ... 2 in Science & Mathematics ➔ Mathematics
[1 / 2(x+h) -2 / 3x ] / h
= [(3x -4x -4h)/(6x(x+h)]/h
= [(-x-4h)/(6x(x+h)]/h
= -(x+4h)/6xh(x+h)
2007-01-31 10:07:37 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
42
2007-01-31 17:49:27 · answer #2 · answered by VodkaTonic 5 · 0⤊ 2⤋
[1 / 2( x + h ) -2 / 3x ] / h
= 1 / 2h( x + h) - 2 / 3xh
= 1 / (2hx + 2h²) - 2/3xh
Use (3xh)(2hx+2h²) as a common denominator:
= 3hx / (3xh)(2hx+2h²) - 2(2hx+2h²) / (3hx)(2hx+2h²)
= [3hx - 2(2hx+2h²)] / (3hx)(2hx+2h²)
= (3hx - 4xh + 4h²) / (3hx)(2hx+2h²)
= (-xh + 4h²) / (3hx)(2hx+2h²)
You could further simplify everything by factoring out an h and well, cancel it out, etc.
2007-01-31 17:54:03 · answer #3 · answered by haxxormaster 2 · 0⤊ 0⤋
((2(x+h)-2/3x)/h
2007-01-31 17:48:27 · answer #4 · answered by Bruce G 2 · 0⤊ 1⤋