east to west.
What is her resulting velocity relative to the ground?
2007-01-31 09:37:35 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
This problem requires that you find the resultant velocity vector. Since the two vectors are at right angles, it becomes very easy. Just use the equation the hypotenuse of a right triangle,
v² = 90² + 45²
v = 101 km/hr (rounded to the nearest km/hr)
2007-01-31 09:45:48 · answer #1 · answered by . 4 · 0⤊ 0⤋
Since the plane is flying north and it is being pushed from east to west the two forces complement one another. They are not opposing so the net speed would be the resulting hypotenus of the triangle formed by her two speeds.
This is where you use the magnitude identity. sqrt((90^2)+(45^2)).
The resulting collective speed is approx. 100.623 km/hr.
2007-01-31 09:42:15 · answer #2 · answered by uahgrad05 3 · 0⤊ 0⤋
just find the resultant vector. do square root of 90^2+45^2 to get 100.6 km/hr
2007-01-31 09:48:05 · answer #3 · answered by climberguy12 7 · 0⤊ 0⤋
(90^2 + 45^2)^1/2 = 100.6 km/hr
2007-01-31 09:46:57 · answer #4 · answered by alwayss_ready 3 · 0⤊ 0⤋