need help with this math problem polynomial equation?

Question

Find All The Solutions x^3 - 4x^2 - 12x + 35= 0

x= or x=

Answer 1

x^3 - 4x^2 - 12x + 35 = 0
(x - 5)(x² + x - 7) = 0

Take (x² + x - 7)
[-1 ± √(1² - 4*1*-7)]/2
(-1 ± √29)/2

So x = {(-1 + √29)/2 , (-1 - √29)/2 , 5 }

Answer 2

x^3 - 4x^2 - 12x + 35= 0
This equation is not factorable so the best method is to try and find roots that almost satisfy the equation. If you try a few numbers you will see that roots are located at approximately -3, 2, and 5
So use Newton's method to isolate the roots to the accuracy desired. Find out where f(x) changes sign and then Newton's method will give you a smaller range where the zero occurs and you can continue getting new estimates. For example the root that is somwhere around 2 is actually at between 2.1921 and 2.1926. So you culd say that the root si 2.192 to 3 significant digits.

If you do not know Newton's method look it up on the Internet.

Answer 3

x³- 4x² - 12x + 35= 0
x(x² - 4x - 12 + 35) = 0
x = 0 ou
x² -4x + 23 = 0
delta = 4² - 4.1.23
delta = 16 - 92
Solution: {There is no roots for that equation: delta < 0}
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Answer 4

try long division, divide up 35 and see which number will divide into the equation without a remainder. like for 7.
x-7 / x^3-4x^2-12x+35.

Answer 5

Use a graphing calculator for this...

do left bound and right bound to find the x intercepts.

x = {2.19, -3.19, 5}

Answer 6

i can't remember how to solve it, but you could graph it in a graphing calculator and find all the places where it crosses the x axis

Answer 7

x= -3.2

x=2.2

x= 5

Answer 8

x1=2.192582404
x2=-3.192582404
x3=5

Answer 9

i think u need techar