ln(20y+16) - ln(4-y) = ln(2x+4) + ln(3-x)?

1 ⤊

ln(20y+16) - ln(4-y) = ln(2x+4) + ln(3-x)?

express the equation in the form y = f(x)

2007-01-31 07:35:38 · 2 answers · asked by Crap_At_Maths 2 in Science & Mathematics ➔ Mathematics

2 answers

ln((20y+16)/4-y)) = ln(( 2x+4)*(3-x)

so (20y+16)/(4-y) = (2x+4)*(3-x)

(20y+16) =(-2x^2+2x+12) *(4-y)

20y +16 = y*(2x^2-2x-12)+ (-8x^2 +8x+48)

y( -2x^2+2x+32) = (-8x^2+8x+48)

y= (-8x^2+8x+48)/(-2x^2+2x+32)

y = (-4x^2+4x+24)/(-x^2+x+16)

2007-01-31 07:50:42 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

What?

2007-01-31 15:40:53 · answer #2 · answered by Katherine 3 · 1⤊ 1⤋