(3x+2)^2=9
THIS IS (3X+2)SQUARED =9
If someone could please help with this by showing step by step how this process works.
thanks
2007-01-31 06:40:23 · 6 answers · asked by lonergirl 1 in Science & Mathematics ➔ Mathematics
Start by taking the square root of both sides:
(3x+2) = 3
Then subtract 2 from both sides
3x = 1
... and divide both sides by 3
x = 1/3
2007-01-31 06:46:24 · answer #1 · answered by Keith P 7 · 1⤊ 2⤋
There are 2 answers:
you must take the square root of both sides and when you do this you get 3x+2 = ± 3. Because the square root of 9 is both 3 and -3.
Then you solve for x in both:
3x+2 = 3
x = 1/3
3x+2 = -3
x= -5/3
2007-01-31 14:50:28 · answer #2 · answered by E 5 · 1⤊ 0⤋
The solution is not to take square root but to multiply the bracket out, so that both roots can be found. The square root method will only give one root.
(3x+2)^2= (3x+2)*(3x+2) which is equal to 9
The brackets expand to:
9x^2+ 12x+4 =9
Taking away 9 from both sides yields
9x^2 +12x -5 = 0
This can be solved by the quadratic equation to yield the two roots as 1/3 and -5/3
2007-01-31 15:44:29 · answer #3 · answered by The exclamation mark 6 · 0⤊ 1⤋
(3x+2)^2=9
take square root of both sides
3x+2 = 3 or -3
3x = 1 or -5
x = 1/3 or -5/3
2007-01-31 14:47:58 · answer #4 · answered by Kirstin 2 · 2⤊ 0⤋
(3x + 2) ^ 2= 9
(3x + 2) = +3 or -3
3x+2 = 3 or 3x +2 = -3
3x = 1 or 3x = -5
x=1/3 or x= -5/3
Remember, second order polynomials have two roots!
Done.
2007-01-31 14:51:13 · answer #5 · answered by Jerry P 6 · 1⤊ 0⤋
(3x+2)^2=9
(3x+2) = sqr(9)
(3x+2) = 3 or -3
3x = 1 or -5
x = 1/3 or -5/3
2007-01-31 14:47:56 · answer #6 · answered by Anonymous · 2⤊ 0⤋