Find the summation of all the 2-digits numbers if divided by 4 it remains 1.
2007-01-31 06:26:43 · 4 answers · asked by Crystal 3 in Science & Mathematics ➔ Mathematics
Find the summation of all the 2-digits numbers that, when divided by 4 the remainder is 1.
2007-01-31 06:38:16 · update #1
I don't think the solution is: 12+17+21...etc. It's too simple. There must be sth. else.
2007-01-31 06:56:20 · update #2
This looks like:
13+17+ ... + 97 =
22*(13 + 97)/2 = 22*55 = 1210
since 22 is the number of terms and 55 is the average term.
2007-01-31 07:22:20 · answer #1 · answered by Phineas Bogg 6 · 0⤊ 0⤋
the sum of all the 2 digit numbers is 4905 so to get the number divisible by 4, subtract 1 (the remainder) from the total to 4904
4904 is divisible by 4 to give 1226
2007-01-31 14:43:06 · answer #2 · answered by ??????????? 2 · 0⤊ 0⤋
13+17+21+25+29... and so forth i dont have time to do all the math but all you have to do is add 1 to a number that is divisable by 4 and add them all together. good luck!
2007-01-31 14:36:42 · answer #3 · answered by Scooter 2 · 0⤊ 0⤋
sorry, this doesn't make sense.
2007-01-31 14:32:03 · answer #4 · answered by Jim 7 · 1⤊ 0⤋