If one leg of a right triangle is 8 inches long, and the other leg is 12 inches long, how many inches long is the triangle's hypotenuse?
I know: 8² + 12² = 208, but the answer isn't the squareroot of 208, but rather is 4 to the squareroot of 16 (see answer: http://www.actstudent.org/sampletest/test1/math/mcorr6.html ). How do you get 4 to the squareroot of 16 from 208?
2007-01-31 06:06:52 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
√(ab) = √a√b
So
208 = 16 * 13
√208 = √(16 * 13)
= √16√13
= 4√13
2007-01-31 06:16:26 · answer #1 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
Let hypotenuse = x
x² = 8² + 12² = 64 + 144 = 208
x² = 16 x 13
x = 4(sq. root 13)
2007-01-31 06:26:11 · answer #2 · answered by Como 7 · 0⤊ 0⤋
undergo in recommendations Pythagoras. The sq. of the hypotenuse, is comparable to the sq. of the different 2 sides. So, if c is the hypotenuse, c^2 = 8^2 + 12^2 = sixty 4 + a hundred and forty four = 208 subsequently, c = sq. rt. 208 =14.40 two
2016-12-16 17:46:30 · answer #3 · answered by dricketts 4 · 0⤊ 0⤋
actually the answer is 4 'times' the squareroot of '13', just like the answer in the link showed. They showed the steps well.
2007-01-31 06:18:08 · answer #4 · answered by Jim 7 · 0⤊ 0⤋
sqrt(208) = sqrt(16 * 13) = sqrt(16)*sqrt(13) = 4*sqrt(13)
The solution shows exactly what I have written.
2007-01-31 06:12:50 · answer #5 · answered by jimvalentinojr 6 · 0⤊ 0⤋
your answer is 4 root 13
4 root 16 is equivalent to the number 16 itself so that answer is wrong
2007-01-31 06:17:37 · answer #6 · answered by Lixender 2 · 0⤊ 0⤋
14.42"
2007-01-31 06:15:42 · answer #7 · answered by slowpokesrool 3 · 0⤊ 0⤋