12x^3 - 3xy^2
2007-01-31 05:10:38 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Factor out 3x:
3x(4x^2 - y^2)
now factor the terms in parentheses (using difference of squares where a^2 - b^2 = (a-b)(a+b)):
3x (2x-y) (2x+y)
There's your answer! Hope this helps! :)
2007-01-31 05:15:59 · answer #1 · answered by disposable_hero_too 6 · 0⤊ 0⤋
factor out the monomial 3x first
3x(4x^2 -y^2)
then there is a binomial difference of squares
3x(2x - y)(2x + y)
2007-01-31 13:32:35 · answer #2 · answered by Ray 5 · 0⤊ 0⤋
put 3x in factor
3x (4x^2 -y^2) = 3x (2x-y) (2x+y)
2007-01-31 13:15:09 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
3x(4x^2 - y^2) = 3x (2x + y) (2x - y)
2007-01-31 13:35:00 · answer #4 · answered by davidosterberg1 6 · 0⤊ 0⤋
3x(4x^2 - y^2)
2007-01-31 13:17:05 · answer #5 · answered by Mitch H 4 · 0⤊ 0⤋
3x(4x^2-y^2) = 3x(2x-y)(2x+y)
2007-01-31 13:30:54 · answer #6 · answered by kellenraid 6 · 0⤊ 0⤋
= 3x(4x² - y²) = 3x(2x - y)(2x + y)
2007-01-31 13:21:00 · answer #7 · answered by Como 7 · 0⤊ 0⤋