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What are the formulas, how have you done that to get that awnswer. Thanks.
I need hellp, please help, I have a test tommorow based on question like these. Thanks

Please follow the link for the examples,

http://www.flickr.com/photo_zoom.gne?id=375669341&size=l

2007-01-31 04:46:38 · 5 answers · asked by fanta m 1 in Science & Mathematics Mathematics

5 answers

Q1)
a)
Surface area of Tower = Surface area of Cylinder + Surface area of Frustum + Surface area of Top Face
SA_T = SA_C + SA_F + SA_TF

SA_C = 2 * pi * r * (r + h)

r = (30.0 / 2) = 15.0
h = 15.0

SA_C = 2 * pi * 15.0 * (15.0 + 15.0)
SA_C = 2 * pi * 15.0 * 30.0
SA_C = 2827.433

SA_F = (pi * r1 * root(r1^2 + h^2)) - (pi * r2 * root(r2^2 + h^2))

h = Height of Frustum
r1 = radius of the bottom base
r2 = radius of the top base

h = 40.0 - 15.0 = 25.0
r1 = (30.0 / 2) = 15.0
r2 = (18.0 / 2) = 9.0

SA_F = (pi * 15.0 * root(15.0^2 + 25.0^2)) - (pi * 9.0 * root(9.0^2 + 25.0^2))
SA_F = (pi * 15.0 * 29.155) - (pi * 9.0 * 26.571)
SA_F = 1373.886 - 751.277
SA_F = 622.609

SA_TF = pi * r^2

r = radius of the top base
r = (18.0 / 2) = 9.0

SA_TF = pi * 9.0^2
SA_TF = pi * 81
SA_TF = 254.469

SA_T = 2827.433 + 622.609 + 254.469
SA_T = 3704.511 m^2

b)
Volume of Tower = Volume of Cylinder + Volume of Frustum
Vol_T = Vol_C + Vol_F

Vol_C = pi * r^2 * h

r = (30.0 / 2) = 15.0
h = 15.0

Vol_C = pi * (15.0)^2 * 15.0
Vol_C = pi * (15.0)^2 * 15.0
Vol_C = 10602.875

Vol_F = 1/3 * h * (B1 + root(B1 * B2) + B2)

h = Height of Frustum
B1 = area of the bottom base
B2 = area of the top base

h = 40.0 - 15.0 = 25.0

B1 = pi * r1^2
r1 = (30.0 / 2) = 15.0
B1 = pi * (15.0)^2 = 706.858

B2 = pi * r2^2
r2 = (18.0 / 2) = 9.0
B2 = pi * (9.0)^2 = 254.469

Vol_F = 1/3 * 25.0 * (706.858 + root(706.858 * 254.469) + 254.469)
Vol_F = 1/3 * 25.0 * (706.858 + 424.115 + 254.469)
Vol_F = 1/3 * 25.0 * 1385.442
Vol_F = 11545.349

Vol_T = 10602.875 + 11545.349
Vol_T = 22148.224

Air space = 65% of total volume

Air space = (65 / 100) * 22148.224
Air space = 14396.346 m^3

2007-01-31 23:07:15 · answer #1 · answered by Olly T 1 · 0 0

Q4: 2.5, 1.6 & 3.0 are your amplitudes which you may state as required. 0.5 or 2.0 before the x refers to whether the cycle is over
180 degrees or over 720 degrees. Short or long? I think that a sine
wave passes through the origin at 0 deg and a cosine is maximum
on the Y-axis at 0 deg. Remember quadrants: sin ++-- cos +--+.

2007-01-31 07:25:57 · answer #2 · answered by BB 7 · 0 0

"stick to graphical approaches" only skill "Draw". yet your diagrams could be wisely drawn. quite you may no longer advise you will get a attempt in this the following day and you do no longer are conscious of it. the two your instructor desires bawled out or you do. you have left it slightly overdue to p.c.. all of it up now...

2016-11-23 17:38:27 · answer #3 · answered by ? 4 · 0 0

Your taking the michael! No one minds helping someone who gets stuck on one question. You want us to do all your homework.

2007-02-03 11:45:28 · answer #4 · answered by lester_day 2 · 0 0

never heard of a sinusodial function before but I will try to help you by giving you these links good luck for the test.
http://faculty.washington.edu/jpalmier/Courses/2001/Math124/PDF/sinusoidal.pdf
http://jwbales.home.mindspring.com/precal/part4/part4.4.html

2007-01-31 04:55:59 · answer #5 · answered by Vixz06 4 · 0 0

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