a. (4,0), (0,-4)
b. (0,-4), (-4,0)
c. (-4,0), (0,-4)
d. (0,4), (4,0)
2007-01-31 04:14:58 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
d.
This is the composite of a strait line passing through a circle.
The only points that satisfy both equations is d
2007-01-31 04:25:03 · answer #1 · answered by davidosterberg1 6 · 0⤊ 0⤋
ok i hope you not making me do your home work. any ways what you have to do is plug the y value in in the first equation which means you will slove for
x^2+(-x+4)^2=16
x^2+( X^2-8x+16) -16=0
2X^2-8x=0
2x(x-4)=0
x=0 or x=4
then we go and solve for the main equation
when x=0 then y =4
and when x =4 then y =0
so the answer will be d wich is (0,4) (4,0)
2007-01-31 12:32:58 · answer #2 · answered by lilly 2 · 0⤊ 0⤋
y=-x+4
thus in x^2+y^2=16, substitute the value of y
therefore x^2+(-x+4)^2=16
x^2+x^2+16=16
2x^2=0
x^2=0
X=0
thus y=-0+4
y=4
therefore (0,4)
replacing x=-y+4, we get (4,0)
and thus ;-) answer is d...(0,4),(4,0)
i hope :-)
2007-01-31 12:36:46 · answer #3 · answered by T-Bone 1 · 0⤊ 0⤋
d
2007-01-31 12:29:55 · answer #4 · answered by ??????????? 2 · 0⤊ 0⤋
Is it D? I hope it is!
2007-01-31 12:24:11 · answer #5 · answered by Anonymous · 0⤊ 0⤋