find the center and radius of the circle with equation: x^2+(y-4)^2=9?

Question

a. (0,4);9
b. (4,0);3
c. (-4,0);9
d. (0,4);3

Answer 1

d
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Reason:
A circle is defined as a set of points such that the distance from any point (x,y) in the set to a fixed point (a,b) , called center, is a constant (r).

(x-a)^2+(y-b)^2 = r^2

Comparing to the standard form gives,
a=0, b=4 and r=3

Answer 2

if X=0 then y= 1 or 7
if Y=0 then X= 3 or -3
knowing this, the radius is 3 and the center is x=0and y=4
thus the answer is D

Answer 3

In (x-h)² + (y-k)² = r², (h,k) is the center and r is the radius.

So reading it off the equation, the center is (0,4) and the radius is 3.

Answer 4

the center is (0,4) and the radius is 3. so i guess that would be D

Answer 5

The form is:

(x - h)² +(y - k)² = r²

Center = (h,k)

For your eq'n, you have: h = 0, and k = 4, and r = 3.

So, your answer would be "d"

:)

Answer 6

correct ans wer is option d
compairing it with
(x-a)^2+(y-b)^2=r^2


a=0, b=4
rad is 3

Answer 7

D

For my favorite Lana. Let's get back together. that other lana l meant nothing to me. It's just you baby.

Answer 8

r=3
c(0,4)

answer is d

Answer 9

d