lim (sqrt x - 1)/ (x-1)
x->1
2007-01-31 02:27:10 · 5 answers · asked by tweetys_01 3 in Science & Mathematics ➔ Mathematics
its just the sqrt x
2007-01-31 02:39:06 · update #1
plz show how u got the answer
2007-01-31 02:46:15 · update #2
lim (√x - 1)/ (x -1)
x->1
=lim 1/ (√x +1), reason:x-1 = (√x+1)(√x-1)
x->1
= 1/2
2007-01-31 02:55:32 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
Because the limit of the numerator and denominator each approach 0, you can use L'hopital's Rule.
f(x) = âx - 1
g(x) = x - 1
lim f'(x) / g'(x)
x->1
lim [ (1/2) * x^(-1/2) ] / 1
x->1
= 1/2 * 1 / 1
= 1/2
2007-01-31 03:14:31 · answer #2 · answered by Kookiemon 6 · 0⤊ 0⤋
Depends on if that's âx - 1 or â(x-1).
2007-01-31 02:34:29 · answer #3 · answered by bequalming 5 · 0⤊ 0⤋
you may also use l hospital's rule diffrentiate both numerator and denominator and put the value
2007-01-31 03:02:21 · answer #4 · answered by tarundeep300 3 · 0⤊ 0⤋
the limit is 0.5
2007-01-31 02:43:08 · answer #5 · answered by giovaney 1 · 0⤊ 0⤋