a. (x-4)^2 /16+(y-2)^2 /4=1
b. (x+4)^2 /16+(y-2)^2 /4=1
c. (y+2)^2 /16+(x+4)^2 /4=1
d. (y-2)^2 /16+(x-4)^2 /4=1
2007-01-31 02:08:20 · 4 answers · asked by lana l 1 in Science & Mathematics ➔ Mathematics
1776
2007-01-31 02:17:26 · answer #1 · answered by piperjoe68 3 · 0⤊ 0⤋
The answer is b) but the ellipse is not determinated givig the center and the position of the mayor axis.
In this case mayor axis= 2a = 8 and minor axis 2b = 4
2007-01-31 12:41:27 · answer #2 · answered by santmann2002 7 · 1⤊ 0⤋
center (-4,2) means you need an (x+4)² term and a (y-2)² term. That eliminates A and D.
Horizontal major axis means that the square term under the (x+4)² term will be larger than the one under the (y-2)² term.
That describes B.
2007-01-31 10:17:17 · answer #3 · answered by bequalming 5 · 2⤊ 0⤋
i worked it out and it comes to B
2007-01-31 10:38:20 · answer #4 · answered by Lana L 2 · 1⤊ 0⤋