Predict the score. Closest score gets best answer. If two people predict the same score then the first one will be chosen as best answer.
Any comments justifying your predicted score welcome.
2007-01-31 00:46:36 · 6 answers · asked by Diarmid 3 in Sports ➔ Rugby
England 24 Scotland 8 (sorry scotland!)
2007-02-02 02:51:23 · answer #1 · answered by FC 2 · 0⤊ 0⤋
England 29 - Scotland 31
Tries Tries
Robinson, Vickery Southwell,DiRollo,Kellock
Pens Pens
Wilkinson 2,Flood 2 Patterson 4
Cons Cons
Wilkinson 1, Flood 1 Patterson 2
Wilkinson to be stretchered off mid-way through the first half after being nailed by Murray. Flood to provide terrible passes and woeful defence for the rest of the match. Consolation try for Vickery at the end but its too little to late.
2007-01-31 09:06:15 · answer #2 · answered by Peter H 2 · 0⤊ 0⤋
England 19 Scotland 22
If the Scottish back row have got any gumption, they will hammer Wilkinson from the start. He is not match fit and still an injury risk. The earlier that the back row do their job, the better the chance for Scotland.
England is still a divided team with a new coach. They were pathetic in the autumn internationals and probably still are!
2007-01-31 16:15:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Scotland 21- 15 England
Johnny Wilkinson to be the only England player contributing to score until he is stretchered off with yet ANOTHER knee injury.
2007-01-31 17:26:05 · answer #4 · answered by Adrian T 2 · 0⤊ 0⤋
England 27 - 12 Scotland
England are at home,
I think Wilkinson will kick well.
Robinson and Lewsey are world class, too much for Scotland to cope with when they are on fire.
I think Farrel will have a good game too.
Cusiter is only just back from injury and without White, they will unfortunately struggle
2007-01-31 08:56:06 · answer #5 · answered by hard as nails 5 · 0⤊ 0⤋
15 - 10. I predict an awful game to watch. Hardly any tries, played in awful conditions. England by a nose. Super 14 starts tonight, got pay TV?
2007-02-01 20:58:57 · answer #6 · answered by red dog 2 · 0⤊ 0⤋