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Is there any other method of comparison ?
Find the overall percentage of Tarun if he gets the following % of marks : MATHS (150 ) 65
CHEMISTRY (130) 35
PHYSICS (120) 50
GEOG. (100) 77
HIS ( 60 ) 80
COMP (40) 80
The no in the bracket is the max marks in that sub. and outside is the % of marks obtained . I solve it in this way but i got wrong answer
65+35+50+77+80+80 / 700*100 = 64.5 %
Can u tell me what is wrong with this method as I have taken percentage of percentages in various subjects.
I know this is a long question but plz reply . i am very confused about it . THANKS

2007-01-30 21:02:17 · 4 answers · asked by gaurav 1 in Science & Mathematics Mathematics

4 answers

i got an overall percentage of 60% solved it by taking the number of questions in the subject and multiplying by the percent to see how many he got right and then adding all correct answers together to get total and dividing by total questions of 600 and then multiplying by 100 to get total percantage of correct answers


you are finding the average of his percentages. its asking for an overall percentage.

2007-01-30 21:20:15 · answer #1 · answered by Rebel T 2 · 0 0

Maths mark = 65% of 150 = 97.5
Chem 45.5
Phys 60
Geog 77
Hist 48
Comp 32
Total marks = 360 out of total 600

Hence overall percentage = 36/60*100
= 60%

So yeah, Rebel T is correct, so why did I bother?
Of course, how these are averaged depends on the educational philosophy of the school. If they say all subjects have to be given equal weight, then your answer is the correct one. But if they are weighted according to the total marks available on each, then it's 60% as we got.

2007-01-30 21:30:15 · answer #2 · answered by Hy 7 · 0 0

Consider the % marks:-
Average % mark = Total % marks / 6
= 387/6 = 64.5%
Comment: Some work required in Chemistry and Physics but good elsewhere!

2007-01-30 21:23:34 · answer #3 · answered by Como 7 · 0 0

the standard speed is the excellent length of the path, divided by using the time it took to traverse the path. the standard speed is the on the instant-line distance from the path's commencing factor to its ending factor, divided by using the time it took to traverse the path. So, the standard speed and standard speed would be comparable whilst the path is a on the instant line. If there is any curvature, the standard speed would be below the standard speed.

2016-11-23 16:55:29 · answer #4 · answered by ? 4 · 0 0

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