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Any math whizzes able to find the integral of (x+x^(3/2))^(-1/2)? If using substitution, what value do you use for u?

2007-01-30 17:56:15 · 2 answers · asked by untitledonald 2 in Science & Mathematics Mathematics

2 answers

Integrate 1/√[x + x^(3/2)] with respect to x.

∫{1/√[x + x^(3/2)]}dx

Let
u² = x
2u du = dx

∫{2u/√[u² + u³]}du = ∫{2u/[u√(1 + u)]}du = ∫{2/√(1 + u)}du
= 4√(1 + u) + C = 4√(1 + √x) + C

2007-01-30 18:33:40 · answer #1 · answered by Northstar 7 · 0 0

[4([x^3/2]+x)^1/2]/([x^1/2]

2007-01-30 18:03:02 · answer #2 · answered by Sarah 2 · 0 0

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