Solve for y:
x/8 + y/2 = 1
Once again, I'm lost. But it's my last question for the night!
2007-01-30 17:43:44 · 6 answers · asked by Arnold 3 in Science & Mathematics ➔ Mathematics
Turn the mixed fractions into common denominators.
x/8 + y/2 = 1
x/8 + 4y/2x4 = 1
x/8 + 4y/8 = 1
(x + 4y)/8 = 1
multiply both sides with 8
x + 4y = 8
4y = 8 - x
y = (8 - x)/4
Answer:
y = 2 - x/4
2007-01-30 17:55:31 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The first thing you want to do is get rid of the fractions. To do this, multiply by a number that 2 and 8 (which is 8) both divide into evenly so that they will cancel out when you multiply everything.
(x/8 *8) + (y/2 *8 ) = (1 *8)
x + 4y = 8
Now move x to the other side of the equation by adding its opposite (-x).
4y = -x + 8
Finally, divide everything by 4.
y = -x/4 + 2
2007-01-31 01:51:29 · answer #2 · answered by T F 4 · 0⤊ 0⤋
Solving y
1. Multply by 2 leads to
x/4 + y = 2 or y = 2 - x/4
2007-01-31 01:58:39 · answer #3 · answered by A S 4 · 0⤊ 0⤋
(x/8) + (y/2) = 1
Multiply everything by 8
x + 4y = 8
4y = -x + 8
y = (-1/4)x + 2
2007-01-31 02:18:05 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
y/2=1-x/8
2(y/2)=2(1-x/8)
y=2-(2x/8)
y=2-(x/4)
2007-01-31 01:57:02 · answer #5 · answered by Sarah 2 · 0⤊ 0⤋
y/2=1-x/8
y=2-2x/8
y=2-x/4
2007-01-31 01:50:13 · answer #6 · answered by Elizabeth 2 · 0⤊ 0⤋