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The balanced equation for Sodium borohydride with water is:

NaBH4 + 2H2O → NaBO2 + 4H2

The borohydride ion would react as:

BH4- + 2H2O → BO2- + 4H2

This first part of this reaction is:

BH4- + H2O → BH3OH- + H2

2007-01-30 18:12:32 · answer #1 · answered by Richard 7 · 13 0

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