find 3 consecutive integers such that the sum of the first and the third is 146. (please tell me when im gonna need this lol honestly.) and thanks to those that have helped me with this i desperatly need help in math cuase i really suck big time.
2007-01-30 16:54:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
the 3 integers are n, n+1 & n+2.
n+n+2=146
2n=144
n=72
the integers are 72, 73 & 74
2007-01-30 17:00:39 · answer #1 · answered by yupchagee 7 · 6⤊ 0⤋
since the sum of 2 numbers that are 2 apart is 146, divide 146 by 2. you get 73. one up and one down means 72+74, which is 146.
the integers are 72,73,and 74.
2007-01-31 01:01:34 · answer #2 · answered by blah 3 · 0⤊ 0⤋
You can write consecutive integers like this:
n+(n+1)+(n+2) because consecutive means one number after another. So, as you can see the first term is n and the third term is (n+2) so:
n+(n+2)=146
2n=144
n=72
72,73,74
2007-01-31 01:00:44 · answer #3 · answered by bluefairy421 4 · 0⤊ 0⤋
The answer as to when you are going to need this: You will probably never need the answer to this specific question, but if you learn how to answer this question, you will have learned a thinking skill that will help you know how to solve problems. Also exercising your brain helps you avoid Alzheimer's disease.
So, You will probably never need the answer to ... (Wait a minute, did I already answer this?) ...
2007-01-31 01:36:14 · answer #4 · answered by smartprimate 3 · 0⤊ 0⤋