ok i need some assistance with this one?

Question

five times a number is 21 less than twice the opposite of the number. What is the nunber?

ok is it something like 5x>21-? thats what im stuck on the opposite of the number i dont get it.. =*[

Answer 1

opposite of the number? well thats tricky, hope that didnt mean to be orientation.

if its reciprocal then u get quadaritic equation 5x=2/x-21
=> 5x2(square) =2-21x
=> 5x2(sq) +21x -2=0

or if y=1/x
then equation is 2y2(sq) -21y -5=0
then take out the roots.

"or better u take its negative number"

oh damn...

all the best for that "opposite" thing.

Answer 2

if a number is, say, x then the opposite number is -x. You see, by the definition: opposites are two numbers that are on opposite sides of the origin (0) on the number line.

Then the equation is like that: 5x = 2(-x) - 21. It goes like that: 5x = -2x - 21; 7x = -21; x = -3. It should satisfy the original question.

Answer 3

5x = 2(-x) - 21 or 5x = -2x - 21

"is" means = and in this case, "less than" means subtract 21 from what comes next, not the < symbol. The opposite of the number would be the negative and then multiply it by 2 for twice. So you can multiply 2 and -x to get -2x.

To solve the equation, you need to get all the x terms on one side by adding the opposite of -2x (which would be +2x) to both sides and then finish solving from there.

Your answer should be -3 if you solve correctly. Good luck!

Answer 4

no no no... what do you mean by opposite of the number? anyway, its something like this

let x = number

5x=2 times opposite of the number-21

Answer 5

u can do it like this. take the no. opposite to teh number as its negative number.
2(-x) - 5x = 21
-2x - 5x = 21
-7x = 21
so, x = -3