Limit Calculations?

0 ⤊

Anybody know the awnser to this?

lim x--> -3

2- squareroot(x^2-5) / x+3

THANKS

2007-01-30 16:33:41 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

lim(2 - √(x^2 - 5)) / (x + 3)) =
x--> -3
lim( - 2x / 2√(x^2 - 5)) =
x--> -3
- (-3) / √(9 - 5)) =
3 / √4) =
3/2

2007-01-30 17:27:47 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋

2-sqrt((-3)^2-5)/((-3)+3)=0

i might have misread it look back at the probelm

2-sqrt((-3)^2-5)/(-3) + 3 =3

2007-01-31 00:41:47 · answer #2 · answered by doomdxxxvi 1 · 0⤊ 0⤋

It's -inf, you can't invoke L'Hopital's rule in this case because the numerator is non-zero.

2007-01-31 00:52:29 · answer #3 · answered by Tangent . 2 · 0⤊ 1⤋

use the L'Hospital theorem

2007-01-31 00:43:44 · answer #4 · answered by sm bn 6 · 0⤊ 0⤋