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Iron has a property such that a 1.00 {\rm m}^{3} volume has a mass of 7.86 \times 10^{3} {\rm kg} (density equals 7.86 \times 10^{3} {\rm kg/m^3} ). You want to manufacture iron into cubes and spheres.

2007-01-30 15:51:17 · 2 answers · asked by Anonymous in Science & Mathematics Physics

ron has a property such that a 1.00 {\rm m}^{3} volume has a mass of 7.86 \times 10^{3} {\rm kg} (density equals 7.86 \times 10^{3} {\rm kg/m^3} ). You want to manufacture iron into cubes and spheres.

also Find the radius of a solid sphere of iron that has a mass of 140 g.

2007-01-30 16:04:17 · update #1

2 answers

v=a^3
and
v=m/p
so
a=qube root of v

a=(140/7.86)^(1/3)=2.61 cm

2007-01-31 07:47:34 · answer #1 · answered by Edward 7 · 0 0

Cube root of (140/7.86) centimeters.

2007-01-30 15:58:24 · answer #2 · answered by Anonymous · 0 0

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