I have 35 nickels and dimes . The value is $2.75. Find how many coins of each kind I have.
2007-01-30 15:49:43 · 5 answers · asked by Nicole H 1 in Science & Mathematics ➔ Mathematics
Nickels = n.
Dimes = 35 - n
n*5 + (35 - n)*10 = 275
5n + 350 - 10n = 275
-5n = - 75
n = 15
35-n = 20
15 nickels = .75
20 dimes - 2.00
total = .75 + 2.00 = 2.75
2007-01-30 15:55:46 · answer #1 · answered by ecolink 7 · 0⤊ 0⤋
Find out the value of a nickel and dime and then trial and error.
Is the value of a nickel 10 cents, 1 dollar, 2 dollars?
Is the value of a dime .05cents, .20 cents, .50 cents?
You really need to know that to solve the problem!
I am from Australia and we just use normal dollars!
Add more info and I can help!
2007-01-30 23:56:50 · answer #2 · answered by Tyler E 2 · 0⤊ 0⤋
There are two equations that you can get from this problem
First
5N + 10D = 275
(Five times the number of nickles plus ten times the number of dimes equals 275 cents)
Second
N + D = 35
(The total number of nickles and dimes equals 35)
Rearrange the second equation to get N= 35-D, and substitute this in for the first one. Im not going to finish your homework for you, but this is a great start.
2007-01-30 23:57:21 · answer #3 · answered by 1234567 3 · 0⤊ 0⤋
you need 2 equations with 2 unknowns
let n be the number of nickels and d be the number of dimes
n + d = 35
0.05n + 0.10d = 2.75
2007-01-30 23:54:27 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Solve
(N * .05) + ((35 - N) x 0.10) = 2.75
for N (number of nickels).
The D = 35 - N
2007-01-30 23:55:33 · answer #5 · answered by frugernity 6 · 0⤊ 0⤋