A rocket rises vertically, from rest, with an acceleration of 2.4 m/s2 until it runs out of fuel at an altitude of 1400 m. After this point, its acceleration is that of gravity, downward.
(a) What is the velocity of the rocket when it runs out of fuel?
I calculated this to be 81.9 m/s
(b) How long does it take to reach this point?
I calculated this to be 34.1 s
(c) What maximum altitude does the rocket reach?
I need help with this one.....answer should be in meters.
(d) How much time (total) does it take to reach maximum altitude?
Need help here too. Answer should be in seconds.
(e) With what velocity does the rocket strike the Earth? (Assume up is positive.)
________________m/s
(f) How long (total) is it in the air?
_________________ s
2007-01-30 15:46:31 · 4 answers · asked by Jessie L 2 in Science & Mathematics ➔ Physics
a and b you did right.
c) use v^2=v^2+2as
s turns out to be 342.2, add that to 1400, turns out to be 1742.2m
d)use v=v+at
t turns out to be 8.4, add to the 34.1, turns out to be 42.5sec
e)use first equation again
v turns out to be 184.8m/s
f)use second equation again
t turns out to be 18.9, add to 42.5, turns out to be 61.4sec
2007-01-30 15:59:51 · answer #1 · answered by climberguy12 7 · 0⤊ 0⤋
I won't re-run the calculations, but you can see if you agree with the following:
a. Use h = 0.5at*2, and solve for t. Then use v=at.
b. Use t from part a.
c. Time from burnout to apogee will be given by t = v/g. Put that into the formula for h (part a) to get height above burnout, and add 1400.
d. Add results from b and c.
e. Use formula for h, yet again, and calculate the time. Then use v = gt.
f. Add time results of parts b, d, and e.
2007-01-30 15:56:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋
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2016-11-23 16:08:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
s = ut + 1/2 a, multiplied by the square of t. a = v - u, divided by t. gravity = 9.8 m/ sec./sec. Draw diagrams & do the math!
2007-01-30 16:01:55 · answer #4 · answered by CLICKHEREx 5 · 0⤊ 0⤋