one more algebra problem last question on homework. help?

Question

The sum of two numbers is 133. Four times the smaller of the two numbers equals three times the greater number. Find the numbers.

Answer 1

x + y = 133
4x=3y

solve for x in one of the problems
4x=3y
x=3y/4

x+y=133
3y/4 + y = 133
multiply everything by 4
4(3y/4) + 4*y = 133*4
3y + 4y = 532
7y = 532
divide by 7
y = 532/7
y=76

x+y=133
x+76=133
x=133-76
x=57

Answer: 57 and 76

Answer 2

let x be one number (smaller)
let y be the other (greater)

x + y = 133
4x = 3y

with the first one, isolate for a particular unknown, let's say for y

y = 133 - x

substitute

4x = 3(133 - x)

4x = 399 - 3x

move the three x to the other side..becomes addition

7x = 399

x = 57

if x + y = 133, then y = 133 - 57 = 76

Answer 3

x+y=133 x=133-y
4x=3y x=3/4y
133-y=3/4y
133=1 3/4y
133/ 7/4= y
y=76
76+x=133
133-76= 57
x=57 y=76!!!

Answer 4

57 and 76

Answer 5

(a + b = 133 (-3)
(4b = 3a

3a + 3b = 399
-3a + 4b = 0
-----------------
7b = 399
b = 57

a + b = 133
a + 57 = 133
a = 133 - 57
a = 76
Answer: a = 76; b = 57.
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Answer 6

57 and 76

This is how I did it....

1. x+y=133

2. 3x=4y

3. 3x-4y=133

now, just use both the 1st and 3rd and substitute and you get the answers of 57 and 76

Answer 7

first, enable x be the ouncesof seeds used, and y be the ouncesof nuts used. so which you get x+y=40 two then, seeds cost 20 cents per ounce, and nuts cost 30 cents per ounce, you may get 20*x is the cost of seeds, and 30*y is the cost of nuts. so which you get 20x+30y=1100 ( use 1100 using fact it fairly is $11=1100 cents) and resolve for x, y x = sixteen, y = 26 the respond is sixteen ouncesof seeds and 26 ouncesof nuts

Answer 8

i got about 65 + 68
try it .......