Adidas sports manufactures volleyballs. They package their volleyballs in 1 cubic foot boxes. The volleyballs fit nicely in the boxes,just touching the sides. To keep the ball from being damaged,Adidas fills the empty space in the box with foam. How much foam is put in each soccer box.
answer starts with a 9 i think has to do with surface area
2007-01-30 14:47:10 · 9 answers · asked by Nick 1 in Science & Mathematics ➔ Mathematics
It's volume, not area.
The boxes are cubes with side length 1 ft, so the volleyballs are spheres with diameter 1 ft and hence radius 1/2 ft. So the volume of the volleyball is (4/3) π r^3 = (4/3) π (1/8) = (π/6) ft^3. So the volume of foam is (1 - π/6) = 0.48 cubic feet.
2007-01-30 14:56:26 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
Volume of box = 1 ft^3
Volume of volleyball = 4/3*pi*r^3
where r is one half the box length = 1/2
so volume of volleyball = 4/3 *pi*1/8
volume volleyball = pi/6
The foam fills in the volume of the box not occupied by the volleyball, or 1 cubic foot - pi/6 cubic feet
so V = (6-pi)/6 cubic feet
V ~0.476 ft^3
2007-01-30 22:56:15 · answer #2 · answered by J 2 · 0⤊ 0⤋
Relatively easy; has to do with volume
Voume of box: 1 foot cubed
If balls touch side of box, diameter is 1 foot. Hence radius is 0.5 of a foot.
Volume of a sphere is : 4/3 pi r^3
Sub in r = 0.5
Volume of a sphere is : 4/3 pi r^3 = pi / 6 feet cubed
Volume of foam = Volume of box - volume of ball
Volume of foam = 1 - pi / 6
Volume of foam = (6 - pi )/ 6
Volume of foam = 0.476401224 feet cubed per box
2007-01-30 22:56:30 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The answere does NOT start with nine, and has to do with volume not surface area.
You want to subtract the (volume of the box) - (volume of ball) = volume of foam.
The volume of the box you know (1 cubic foot). The volume of the ball is (4/3)*pi*r^3
R is the radius of the ball, so half a foot...
so
4/3*3.1415*.0125 = .524
so the volume of the foam is
1-.524 = .476 cubic feet (or 823 cubic inches)
This is a pretty easy problem... I suggest you study more.
2007-01-30 23:03:16 · answer #4 · answered by Kevin F 2 · 0⤊ 0⤋
calculate the volume of the box and ball and subtract them. The difference will be the volume of foam used.
2007-01-30 22:51:04 · answer #5 · answered by Sporadic 4 · 2⤊ 0⤋
all you do is find the volume of the whole box and subtract volume of ball.
volume of a sphere is 4/3*pi*r^3
so do 1-(4/3)(pi)(.5)^3
which equals .476
surface area has nothing to do with it.
this is correct
2007-01-30 23:08:09 · answer #6 · answered by climberguy12 7 · 0⤊ 0⤋
Volume of box = 1 ft^3 = 1728 in^3
Volume of ball = 4 * pi * r^3 / 3 = 12.566 * (0.5)^3 / 3 = 0.5236 ft^3
Volume of foam = 1.0000 - 0.5236 = 0.4764 ft^3 = 823.2 in^3
2007-01-30 23:02:58 · answer #7 · answered by hznfrst 6 · 0⤊ 0⤋
calculate the mass of the ball and the area of the box- subtract the mass of the ball and that's how much foam you put in.
2007-01-30 22:53:35 · answer #8 · answered by Zaxop 3 · 0⤊ 2⤋
this is too easy boy do yourown work
2007-01-30 22:52:02 · answer #9 · answered by lilgbitch 1 · 0⤊ 2⤋