Carol drops a stone into a mine shaft 394 meters deep. How soon after she drops the stone does she hear it hit the bottom of the shaft?
2007-01-30 14:02:34 · 6 answers · asked by eldiablo049@sbcglobal.net 1 in Science & Mathematics ➔ Physics
about 39.4sec given the time it takes for the sound to travel back top side Id say 40 seconds would be close inanimate objects fall at 32 ft. per second 32 ft is about 10 meters 394 divided by 10 boom 39.4 seconds
2007-01-30 14:12:41 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Ignoring air resistance
Falling time, Tf = sqrt[2 . h / g] = sqrt [2 . 394 / 32] seconds
Sound travel time, Ts = h / velocity of sound = 394 / 1125 seconds
Total time, Tt = Tf + Ts
Use your calculator and sail
2007-01-30 14:17:41 · answer #2 · answered by Sheen 4 · 1⤊ 0⤋
Using d=0.5at^2
It will take the stone 8.97 sec to hit bottom, ignoring air resistance.
Sound travels at approximately 340m/s, so it will take an additional 1.15 sec for the sound to come back up the mine shaft.
Thats a total of approx 10.1 seconds to hear the sound.
2007-01-30 14:11:43 · answer #3 · answered by sparbles 5 · 0⤊ 0⤋
V*2-U*2= 2 A S(U =0, A = 9.8 M/S*2, S = 394 M )
FROM THIS FIND V
V = U + AT ( FROM THIS FIND T)
2007-01-30 14:18:11 · answer #4 · answered by calmserene 4 · 0⤊ 0⤋
Depends on the weight of the stone and the total surface of air resistance it has....a ball of granite may drop faster than a brick of sandstone....
2007-01-30 14:06:32 · answer #5 · answered by comtnman2003 3 · 0⤊ 0⤋
pretty damned quickly
2007-01-30 14:06:28 · answer #6 · answered by Anonymous · 0⤊ 0⤋