if you were given a triangle with the angles marked as X (squared), 5x, and 3x how do you solve for x?

Answer 1

All three angles have a sum of 180.

x^2 + 5x + 3x = 180

Collect like terms on the left side.
x^2 + 8x = 180

Subtract 180 from both sides.
x^2 + 8x - 180 = 0

Now, you can either factor or use the quadratic formula.

Factors of 180 that subtract to 8....18 and 10.
(x + 18)(x - 10) = 0

x + 18 = 0 or x - 10 = 0
x = -18 or 10

In this case we can only use a positive answer (degrees in a triangle shouldn't be negative).

x^2 = 100
5x = 50
3x = 30

100 + 50 + 30 = 180.

Answer 2

Well, the angles in a triangle must always add up to 180

So x^2 + 5x + 3x = 180

x^2 + 8x = 180

x^2 + 8x - 180 = 0
Then we use the quadratic formula to find...

That x can either be 10 or -18. Since an angle cannot be a negative number, x must equal 10.

Therefore, the angles are:

100, 50, and 30.

Answer 3

x^2+5x+3x=180 because there's 180 degrees in a triangle. so it would be x=10 so one angle would be 100, 50 and 30

Answer 4

A + B + C = 180

or in our case

x^2 + 5x + 3x = 180
x^2 + 8x = 180
x^2 + 8x - 180 = 0

x = (-b ± sqrt(b^2 - 4ac))/(2a)

x = (-8 ± sqrt(64 - 4(1)(-180)))/(2(1))
x = (-8 ± sqrt(64 + 720))/2
x = (-8 ± sqrt(784))/2
x = (-8 ± 28)/2
x = (20/2) or (-36/2)
x = 10 or -18

since you can't have negative length

x = 10

ANS : 100°, 50°, and 30°

Answer 5

x^2 + 5x + 3x = 180
x^2 +8x - 180 = 0

use the quad formula to solve

Answer 6

x^2+8x-180=0
Use factoring to find two values for x, the non-negative number is the answer.