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please help me solve this integral..i am stuck

integral: square root of 9 +4x^2 dx

2007-01-30 13:15:38 · 2 answers · asked by re_defin3d 2 in Science & Mathematics Mathematics

2 answers

try taking the 9 out of the sqrt

3*sqrt(1+ (4/9)x^2) dx

then use the trig identity of 1 + tan^2 = sec^2

let tan@=(2/3)x

and do d@/dx on it

if i get a chance to dig further i will :p

2007-01-30 13:42:03 · answer #1 · answered by wendywei85 3 · 0 0

try trigonometric substitution

2007-01-30 13:28:33 · answer #2 · answered by Jack 1 · 0 0

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