I have an algebra story problem that I've worked like 10 times and I have no idea how to get the answer!! Can anyone show me how to work it out??---- Connie is 2/3 as old as her cousin. The sum of their ages is 45. How old are Connie and her cousin?---- I could really use some help!!
2007-01-30 12:35:29 · 5 answers · asked by shelleybee 2 in Science & Mathematics ➔ Mathematics
Let c = connie, a = cousin
c + a = 45
c = 2/3a
so by substitution
2/3a + a = 45
5/3 a =45
a = 27, so c = 18
2007-01-30 12:42:38 · answer #1 · answered by leo 6 · 0⤊ 0⤋
Let c = her cousin's age . The Connie's age is 2/3 c
c + 2/3 c = 45
Change c to 3/3 c so you can add it to 2/3 c
5/3 c = 45
Now divide both sides by 5/3, which is like multiplying by 3/5
That will give you c. Then subtract that from 45 to get Connie's age.
2007-01-30 20:44:43 · answer #2 · answered by hayharbr 7 · 0⤊ 0⤋
well you would use this:
2/3x for connie age
x for her cousins age.
2/3x + x = 45
combine like terms.
1 1/3x + 45
divide
x = 27
so connie's cousin is 27 years old, and connie is 2/3 her age.
we would plug the 27 in for x.
2/3(27) = connie's age.
connie is 18, and her cousin is 27.
2007-01-30 20:44:12 · answer #3 · answered by k 4 · 0⤊ 0⤋
Connie is 2/3 as old as her cousin. Therefore, connie = 2/3X where X is connie's cousin.
X + 2/3X = 45
5/3X = 45
5X = 135
X = 27
Connie is 18, her cousin is 27.
2007-01-30 20:46:32 · answer #4 · answered by Salek 4 · 0⤊ 0⤋
x + 2/3x = 45
5/3x=45
x=27
cousin=27
connie=18
2007-01-30 20:44:00 · answer #5 · answered by lizbiz707 3 · 0⤊ 0⤋