I'm trting to solve for y, but having some trouble isolating the y.
2007-01-30 11:53:08 · 5 answers · asked by RogerDodger 1 in Science & Mathematics ➔ Mathematics
ahg! I keep forgetting to factor out stuff;
thanks guys, I should know that by now! :)
2007-01-30 12:16:17 · update #1
take out the y
y(2x-4) = -3x-1
y= (-3x-1) / (2x-4)
2007-01-30 12:04:44 · answer #1 · answered by 7 · 1⤊ 0⤋
2xy - 4y = -3x - 1
*factor out multiple y on left side*
y(2x - 4) = -3x - 1
*divide by (2x - 4) on both sides to get y alone*
y = (-3x - 1) / (2x - 4)
2007-01-30 20:12:14 · answer #2 · answered by CaineOmega 1 · 0⤊ 0⤋
2xy-4y = -3x-1
(2x-4)y = -3x-1
y = (-3x-1) /(2x-4)
2007-01-30 20:05:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
2y ( x - 2) = - 3x - 1
2y = ( -3x-1)/(x-2)
y = (-3x-1) / 2(x-2)
2007-01-30 20:12:33 · answer #4 · answered by cute_gurl 1 · 0⤊ 0⤋
y= (-3x-1)/(2x-4)
2007-01-30 20:05:46 · answer #5 · answered by Brett B 2 · 0⤊ 0⤋