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4 answers

the heavier boy wins, as he has more momentum.

momentum = mass * velocity.

2007-01-30 11:42:48 · answer #1 · answered by synth 2 · 0 1

Several possibilities...

1) The lighter boy ceases his velocity, or reverses course from the impact (basically gets knocked down), and the larger boy continues on at a slower pace.

2) The larger boy plows into the smaller boy and carries him along after the impact. Both boys act as one mass, moving in the same direction as the larger boy, but with a slower velocity.

3) One or both boys are deflected, with a reduction in both of their velocities. How much depends on the deflection and their weights.

4) The boys knock each other directly back, transfering their motions to each other. The larger boy moves more slowly, the smaller boy more quickly.

These results all reflect varying degrees of elastic and inelastic collisions.

2007-01-30 12:04:58 · answer #2 · answered by The Ry-Guy 5 · 0 1

speaking from journey because the lighter guy, I usually were given knocked backwards 10 ft by skill of the air at the same time as the massive guy slightly slowed down and continued to flow ahead. this suggests the the collision is a blend of "elastic" and "inelastic". In an inelastic collision, momentum is exchanged from one merchandise to the different and the gadgets flow off one after the different, each and each on a clean route with the others unique momentum. In an inelastic collision, the gadgets momentarily "connect jointly" and combine their momentum to flow off jointly on a similar route. The momentum of both boy should be computed via multiplying his mass cases his velocity. So what takes position after both boys make contact relies upon on no matter if the contact is, in football words, a block or a address. no matter if that is a block (or "inelastic" collision), in which neither boy grabs the different, then both boys will substitute momentum with the smaller boy transferring backwards a lot swifter than he grow to be initially transferring ahead and the bigger boy transferring backwards besides, yet much better slowly. no matter if that is a "address" (or "elastic" collision) the position one boy grabs the different, then both will flow interior a similar route because the bigger boy's unique action, yet at a slower velocity because the momentum of the smaller boy is subtracted from the momentum of the bigger boy. word that in both circumstances, momentum is conserved, regardless of the indisputable fact that the form of collision determines how that is conserved.

2016-12-03 06:24:35 · answer #3 · answered by ? 4 · 0 0

The one with less weight would fall down

2007-01-30 11:42:55 · answer #4 · answered by i_am_bee2 3 · 0 1

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