Physics Question? (Fluid dynamics)?

Question

A 10.0 m tall open water tank has a nozzle 2.0 meters from it's bottom. The nozzle has a cross sectional area of 0.016 meters squared. What is the rate of discharge from the nozzle, assuming that the water has no kinetic energy in the tank?

Answer 1

Velocity of discharge will be V=sqroot(2gh) where h is the water over the nozzle, so it's 8 meters.
So V= sqroot(2*9.8*8)= 12.522 m/s

So just multiply per the section of your nozzle
12.522*0.016 = 0.2 m3/s = 12 m3/min

very easy

ah and the water will arrive at 8 meters of distance from the tank.
but you will find the formula for that calculation ! :-)