How much of each type shoud be used to make a 20 pound blend that sells for $10.60 per pound?
2007-01-30 09:07:42 · 6 answers · asked by Pretty_baby 1 in Science & Mathematics ➔ Mathematics
$11 * x + $10 * y = $10.60 * 20
x + y = 20
11x + 10y = 212
x + y = 20
So,
10x + 10y =200
Now,
11x + 10y=212
10x+10y =200
Subtract the equations:
x = 12
x + y=20 => y=8
Thus: 12 pounds of $11 coffee and 8 pounds of $10 coffee.
Done.
2007-01-30 09:18:48 · answer #1 · answered by Jerry P 6 · 1⤊ 0⤋
Let x=the amount of fresh roast coffee. Then the amount of vanilla can be expressed as 20-x. Multiply each kind by its value, add them together, and equate it to the mixture times its value:
11x+10(20-x)=20(10.60)
11x+200-10x=212
x+200=212
x=12
12 pounds of fresh roast, and 8 pounds of vanilla.
2007-01-30 17:16:51 · answer #2 · answered by Chris S 5 · 0⤊ 0⤋
40% fresh roast and 60% vanilla so 8 and 12 pounds
2007-01-30 17:17:58 · answer #3 · answered by ? 5 · 0⤊ 0⤋
First off starbuck coffee sucks consumers report tested all coffee in USA found Dunkin Donuts Coffee to the the best at under $7.00 a lb
2007-01-30 17:15:13 · answer #4 · answered by Anonymous · 0⤊ 1⤋
let (20 -x) be the number of pounds of fresh roast
let x be the number of pounds of vanilla
The ratio
20 lb
--------------------------------------------- = 10.60 lb/$
11 $/lb *(20-x) lb + 10 $/lb (x) lb
Work that out at least for your homework.
OR look at the answer above... another way to work it.
2007-01-30 17:20:54 · answer #5 · answered by Steven A 3 · 0⤊ 0⤋
6/5 lb. of fresh roast
4/5 lb. of vanilla.
2007-01-30 17:14:21 · answer #6 · answered by smawtadanyew 2 · 0⤊ 0⤋