For a certain 3-digit number, inter-changing the first and last digits gives a 3-digit number 297 less than the original number. Doubling the first and last digits of the original number gives a 3-digit number and increases the sum of the digits to 15. What is the number?
2007-01-30 08:15:49 · 5 answers · asked by abs of steel 3 in Science & Mathematics ➔ Mathematics
451
Interchanged = 154. 451- 154 = 297
now doubled digits. 451 = 852. Sum of the digits is 15.
2007-01-30 08:21:32 · answer #1 · answered by smawtadanyew 2 · 0⤊ 0⤋
second part first. 2a+b+2c = 15; a & c < 4 a >0
First part 100a+10b+c - (100c + 10 b + a) = 297
99a-99c = 297
a-c=3
c = 0 or 1, a = 3 or 4
back to 15 clue:
3b0 --6b0 ; b = 9 OR
4b1 --8b2; b = 5
try 451-154 = 297. I can dig it.
The original number = 451.
See ya.
2007-01-30 16:23:16 · answer #2 · answered by bequalming 5 · 0⤊ 0⤋
390 or 451
1. 390 - 093 = 297 ; 451-154 = 297
2. 690 -> sum of digits is 15 ; 852 ->15
2007-01-30 16:25:27 · answer #3 · answered by catarthur 6 · 0⤊ 0⤋
693 ?
2007-01-30 16:20:05 · answer #4 · answered by maegical 4 · 0⤊ 0⤋
a
2007-01-30 16:18:52 · answer #5 · answered by Flangina 2 · 0⤊ 0⤋