Avogadro's number is equal to 6.0221 x 10^23. How many potassium ions are in 5.00g of potassium sulfate?
2007-01-30 08:03:02 · 3 answers · asked by Tracey Lee ♥ 2 in Science & Mathematics ➔ Chemistry
Potassium sulfate K2SO4 has a molar mass of 136.17 g/mol. When ionized it will created two K+ ions
so 5 g represents 2x5/136.17 mol = 4.422 x 10^22 ions
2007-01-30 08:10:36 · answer #1 · answered by catarthur 6 · 1⤊ 0⤋
Determine the ratio of potassium to sulfate; do this by looking at the chemical formula. If it is KSO4, then it would be a 1:1 ratio so that would mean that 2.5g of that substance is potassium. Follow your units to set up the equation, basically you'll end up multiplying your grams by avogadro's number and that will give you the number of mols in solute. Been a while but I think that's right. Hope it helps...
2007-01-30 16:10:21 · answer #2 · answered by c_macleod_us 2 · 0⤊ 3⤋
here's a hint
1) write the chemical formula for potassium sulfate. use google if you need to.
2) calculate the molecular weight of potassium sulfate
3) calculate the moles of potassium sulfate. moles = mass/ molecular weight
4) calculate the number of molecules of potassium sulfate
5) calculate the number of atoms of potassium
answer
5 g x (1 mole/136.27 g) x ( 2 mole K/ 1 mole K2SO4) x (6.022 x 10^23 atoms K / mole K ) = ????
2007-01-30 16:12:14 · answer #3 · answered by Dr W 7 · 0⤊ 0⤋