solve>(5)^(2/3)?

Question

I need to know how to solve a power that is a fraction in itself for example 5^(2/3)

Answer 1

um.............i think it's 2.924017738 (Or to nearest 100) 2.92

if im the 1st person 2 get it right, will u pick me as best answer???????? i'll blow u a kiss!!!!!!!!!!!!!

Answer 2

5^(2/3) would just mean to square 5 then take the cube root of that answer (for example, the 1/2th power is equivalent to the square root). In this case, 5^2 = 25 isn't a perfect cube, meaning that 5^(2/3) won't be a rational number. However, seeing as 27^(1/3) is just 3, it'll be just a bit under 3.

Answer 3

Using the rule of a^(bc) = (a^b)^c, you can take a^(b/c) and get (a^b)^(1/c). A number that's raised to the power of 1/N is the same as taking the Nth root of that number. So in this case:

(5)^(2/3) = (5^2)^(1/3) = 25^(1/3) = the cube root of 25, which is approximately 2.9240

Answer 4

5^(2/3)=(5^2)^(1/3)=25^(1/3) use the calculator that comes with windows.

enter 25
click x^y
click (
enter 1/3
click )
click =

answer of 2.9240177382128660655067873601379 will be displayed.

Answer 5

in general let we have (5)^(a/b) u have to do this step by step first u do 5^a then in step 2 u calculate the bth roots of (5^a)
for ur question first we have 5^2=25
then we have to calculate the cubic root of 25 which is ur answer (25)^(1/3) find it with calculator!

Answer 6

5^(2/3) = cubed root of 5^2 = cubed root of 25. Check out this site: http://www.purplemath.com/modules/exponent5.htm

Answer 7

(5)^(2/3)
= (5^2)^1/3
= 25^1/3
= cube root (25)

Answer 8

this means you take quberoot of 5 and then square it. of course you would need calculatter for this