I cannot figure out how to display this numerically, someone pls help.
A (1.3) B(5,7) C(4,8) and D (a,b) form a rectangle find a,b
Now I have come up with so far the rules, that if it is a rectangle then AB and CD must be parallel so gradient AB = gradient CD which has left me with
(7-3) 8-b
------ = ------
5-1 4-a
4/4 = 8-b/4-a
Now I know here that obviously b is 4 and a is 0, but from the above a could equal 2 and b could equal 6 for all the layma knows
So then i went and said, for it to be a rectangle AB must be perpendicular to BC, I found ab gradient to be 1, so therefore BC gradient must be -1 and as a result
So therefore I said that 7-3/5-1 * b-3/a-1 must equal -1
therefore 1* b-3/a-1 must equal -1.
Now the only number that multiplies 1 to acheive -1 is -1
so b-3/a-1 = -1
but i have no idea where to take it from here, do I form a simualtaneous equation to work the rest out or what??
2007-01-30
05:54:29
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4 answers
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asked by
John W
2
in
Science & Mathematics
➔ Mathematics