1/5rt5-4rt3
=5rt5+4rt3/125-48
==5rt5+4rt3/77
2007-01-30 05:40:51
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answer #1
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answered by raj 7
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1 / (5â5 - 4â3)
When the denominator looks like a+b and there's a square root involved, multiply top and bottom by the conjugate (a-b) to get rid of the square root:
(1 / (5â5 - 4â3)) * (5â5 + 4â3)/(5â5 + 4â3)) =
(5â5 + 4â3) / ((5â5 - 4â3)(5â5 + 4â3)) =
(5â5 + 4â3) / ((5â5)^2 - (4â3)(5â5) + (4â3)(5â5) - (4â3)^2) =
(5â5 + 4â3) / (5*25 - 16*3) =
(5â5 + 4â3) / (125 - 48) =
(5â5 + 4â3) / 77
2007-01-30 05:46:53
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answer #2
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answered by Anonymous
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Multiply top and bottom by (5 x 5^½ + 4 x 3^½)
= (5 x 5^½ + 4 x 3^½)/(125 - 48)
= (5x5^½ + 4x3^½) / 77
p.s. I would like to know how geezerbill shows the square root of a number by using a square root sign as opposed to using ^1/2
2007-01-30 05:53:37
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answer #3
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answered by Como 7
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To rationalize the denominator, you need to multiply both the numerator and the denominator by the conjugate form of the denominator. That is, since you have:
(5 * sqrt(5)) - (4 * sqrt(3))
The conjugate form is
(5 * sqrt(5)) + (4 * sqrt(3))
Then, your numerator will be:
(5 * sqrt(5)) + (4 * sqrt(3))
And the denominator will be the conjugate times what you had originally, or:
(5sqrt(5)*5sqrt(5)) + (5sqrt(5)4sqrt(3)) - (5sqrt(5)4sqrt(3)) - (4sqrt(3)4sqrt(3))
This simplifies to:
(5sqrt(5)*5sqrt(5)) - (4sqrt(3)4sqrt(3))
(5 * 5 * sqrt(5) * sqrt(5)) - (4 * 4 * sqrt(3) * sqrt(3))
(125) - (48)
77
So, your final fraction is:
(5 * sqrt(5)) + (4 * sqrt(3))
----------------------------------
77
2007-01-30 05:46:27
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answer #4
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answered by Doug 2
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1/[(5â5)-(4â3)]
=1/[(5â5)-(4â3)] * [(5â5)+(4â3)] /[(5â5)+(4â3)]
=[(5â5)+(4â3)] /[(5â5^2)-(4â3^2)
=5â5+4â3/125+48
=5â5+4â3/173
2007-01-31 20:19:49
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answer #5
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answered by honey 3
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you multiply by [5(sqr5) + 4(sqr3)]/[5(sqr5) + 4(sqr3)] to rationalise the denominator and you'll get
[5(sqr5) + 4(sqr3)]/77
2007-01-30 05:43:12
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answer #6
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answered by rfedrocks 3
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1/(5sqrt(5) - 4sqrt(3)) * (5sqrt(5) + 4sqrt(3))/(5sqrt(5) + 4sqrt(3))
= (5sqrt(5) + 4sqrt(3))/77
2007-01-30 05:44:29
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answer #7
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answered by onewingedangel37 1
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............1............
--------------------- ???
5sqrt(5)-4sqrt(3)
You need to multiply by 5sqrt(5)+4sqrt(3) OVER 5sqrt(5)+4sqrt(3)
You get
5sqrt(5)+4sqrt(3)
----------------------
25*5-16*3
Which is equal to
5sqrt(5)+4sqrt(3)
----------------------
...........77.............
2007-01-30 05:45:45
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answer #8
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answered by Anonymous
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