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There's 365 days a year. Each month varies according to days, from 28-31.

My question is, how many odd-numbered days and even-numbered days are there in a year?

jan.1st = odd
jan. 2nd = even
march. 7 = odd
nov. 31 odd
.
.
.
... and so on...

2007-01-30 05:28:35 · 8 answers · asked by nissin67 2 in Education & Reference Trivia

8 answers

Assuming it's not a leap year, there are 7 months with an odd number of days, if we exclude those 7 days you would have the same number of even & odd days So the formula is this:

(Total days - 7 ) / 2 = even number of days
( 365 - 7) / 2 = 179

Add the excluded days back in and you have the odd number of days. 179 + 7 = 186

Of course in a leap year you would be excluding 8 days so the odd days goes up by one.

2007-01-30 05:53:07 · answer #1 · answered by DZ 2 · 1 0

Days Of The Year Numbered

2016-12-12 17:11:30 · answer #2 · answered by ? 4 · 0 0

This Site Might Help You.

RE:
How Many Odd/Even Numbered Days in a year?
There's 365 days a year. Each month varies according to days, from 28-31.

My question is, how many odd-numbered days and even-numbered days are there in a year?

jan.1st = odd
jan. 2nd = even
march. 7 = odd
nov. 31 odd
.
.
.
... and so on...

2015-08-10 04:56:11 · answer #3 · answered by Olia 1 · 0 0

I had mixed feelings about this question, but it started bugging me, so I had to answer it anyways: 179 even, 186 odd. The even's an odd number, the odd's an even number. Ha!

2007-01-30 05:40:48 · answer #4 · answered by mina_lumina 4 · 4 0

187 Odd days and 178 even days, except for Leap Year were there are 179 even days.

2007-01-30 05:41:23 · answer #5 · answered by Anonymous · 1 3

365

2016-08-05 00:42:34 · answer #6 · answered by ? 1 · 0 0

odd/even
jan: 16/15
feb: 14/14 (or 15/14 if leap year)
mar: 16/15
apr: 15/15
may: 16/15
june: 15/15
july: 16/15
aug: 16/15
sep: 15/15
oct: 16/15
nov: 15/15
dec: 16/15

You do the math - I'm bored now.

2007-01-30 05:37:37 · answer #7 · answered by Anonymous · 1 1

your odd alright

2007-01-30 05:33:14 · answer #8 · answered by jim 3 · 0 1

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