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5 answers

f(1) = 2
f(2) = 4
f(3) = 6
ect

you could say that f(n)=2*n

2007-01-30 05:12:27 · answer #1 · answered by Anonymous · 0 0

enable n be the numbers place in the series, so the 1st variety (n=a million) is two; the 2nd variety (n=2) is 4; and so on. The numbers in the series are stumbled on by x=2*n. the version between any 2 words is two*(n2 - n1) the place n2 (n sub 2 - i can't do subscript right here) is the placement of the bigger variety and n1 (n sub a million) is the smaller. d = 2*(n2 - n1)

2016-10-16 07:29:51 · answer #2 · answered by ? 4 · 0 0

what is the following?

anyway, the formula for arithmetic progression is:

Tn = 2a + (n - 1)d

(where 'Tn' is the nth term, 'a' is the first term and 'd' is the common difference)

Sn = [n(a + l)]/2
= {n[2a + (n-1)d]}/2

(where 'l' is the last term and 'Sn' is the summation of the all the terms from the first to the nth term)

2007-01-30 05:14:43 · answer #3 · answered by rfedrocks 3 · 0 0

12 even numbers

2007-01-30 05:13:39 · answer #4 · answered by maussy 7 · 0 0

find what?

2007-01-30 05:22:53 · answer #5 · answered by Anonymous · 0 0

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