3x^2-12= O can any 1 answer this one to??

Answer 1

First: factor the expression - find the least common factor which is, "3" > multiply 3 by the missing terms to get "3x^2 - 12"...

3(x^2 - 4) = 0

Sec: continue to factor the expression in parenthesis = the difference of squares...

3(x + 2)(x - 2) = 0

Third: solve the two x-variables - set both parenthesis to "0"...

a. x + 2 = 0

*Isolate "x" on one side - subtract "2" from both sides (when you move a variable to the opposite side, always use the opposite sign)...

x + 2 - 2 = 0 - 2
x = - 2

b. x - 2 = 0

*Add "2" to both sides...

x - 2 + 2 = 0 + 2
x = 2

Solution: 2 and -2

Answer 2

x = 2

Answer 3

3x^2 - 12 = 0 (Add 12 to both sides)
3x^2 = 12 (Divide both sides by 3)
x^2 = 4 (Take square root from both sides)
x = +2 or -2
QED

Answer 4

3x^2-12 = 0 (Add 12 on bothsides of the equation)
+12 = +12
_____________
3x^2 = 12 (Now divide by 3 on bothsides)
3x^2 /3 = 12/3 ( now you will get :)
x^2 = 4 (Now find the squre root of both sides)
x = -2 or +2 ( This is your answer)

Answer 5

3x^2-12 = 0
3x^2= 12
x^2 = 12/3 = 4
x = 2 or -2

Answer 6

Alright..this question is fairly simple =).

First, transfer -12 to the other side. Thus, 3x^2 = 12

Then divide both sides by 3.
x^2 = 4

Square both sides.
x = + or - 2

DONE!

Answer 7

divide by 3
x^2-4=0
(x-2)(x+2)=o
x=2 x=-2

Answer 8

3x² - 12 = 0

3x² - 12 + 12 = 0 + 12

3x² = 12

3x² / 3 = 12/ 3

x² = 4

√x² = √4

x = 2

The answer is x = 2

- - - - - - - - - -s-

Answer 9

3x^2 = 12
x^2 = 4
x = 2