math problem, average rate of change?

Question

what is the average rate of change of g(x)=2x-3 between the points (-2,-7) and (3,3)?

Answer 1

To find "average rate of change" take the derivative and plug in the points.

In this case, it's a linear equation, so the rate of change is the slope... 2.

Answer 2

Differentiate f'8a9013a75b3a29277697b2b108bfbe1x8a9013a75b3a29277697b2b108bfbe1 = dv/dx = 3x8a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe1; so as that the value of replace at x = (4.001)^2 is = 38a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe1 = 8a9013a75b3a29277697b2b108bfbe18 and at x = 8a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe1 is 3[8a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe1] ~ 8a9013a75b3a29277697b2b108bfbe18 8a9013a75b3a29277697b2b108bfbe1close to 8a9013a75b3a29277697b2b108bfbe188a9013a75b3a29277697b2b108bfbe1; so the standard ROC between those 2 factors is approximately 8a9013a75b3a29277697b2b108bfbe188a9013a75b3a29277697b2b108bfbe1 comparable deal, differentiate V'8a9013a75b3a29277697b2b108bfbe1p8a9013a75b3a29277697b2b108bfbe1 = -9 p8a9013a75b3a29277697b2b108bfbe1-(4.001)^2; so at V'8a9013a75b3a29277697b2b108bfbe1p = 8a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe1 = - 9/8a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe18a9013a75b3a29277697b2b108bfbe1; you're able to do the math8a9013a75b3a29277697b2b108bfbe1 word, the unfavorable sign exhibits the quantity of air decreases below increasing atmospheric pressure8a9013a75b3a29277697b2b108bfbe1

Answer 3

Differentiating the function g(x) i.e., d/dx (2x - 3) with respect to x yields the rate of change as 2, which is a constant, and thus, there will be NO change in g(x), between the above two points. I only hope, that you have stated the question correctly; else the above answer, will NOT apply.

Answer 4

You could plot the points and join them up to form a right angled triangle, vertical side = 10 and horizontal side = 5
Gradient = 10/5 = 2 (average rate of change)
Alternatively if you differentiate g(x), you will obtain g `(x) = 2 which is the average rate of change.