2007-01-29 20:39:50 · 7 answers · asked by Random G 3 in Science & Mathematics ➔ Mathematics
you have:
y = x/2 -1/2
change x's to y's & y's to x's:
x = y/2 -12
solving this new equation yields the inverse:
y = 2x + 1
2007-01-29 20:45:40 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Write it as y = x/2 - 1/2
Then work on the equation until you have it in the form:
x = some expression involving y
This is the inverse function.
2007-01-30 04:45:16 · answer #2 · answered by Gnomon 6 · 1⤊ 1⤋
Let y = F(x)= x/2 - 1/2
x = y/2 - 1/2
2x = y - 1
2x + 1 = y
Inverse F(x) = 2x + 1
2007-01-30 05:40:23 · answer #3 · answered by Northstar 7 · 0⤊ 0⤋
2x+1
2007-01-30 06:23:26 · answer #4 · answered by Iman S 2 · 0⤊ 0⤋
f (x) x f^(-1)x = 1
(x/2 - 1/2) x f^(-1)x = 1
f^(-1)x = 1/(x/2 - 1/2) = 2/(x -1)
Check f(x) x f^(-1)x = (x/2 - 1/2 ) x 2/(x-1)
= (1/2 )(x - 1) x 2/(x - 1) = 1 as required
2007-01-30 05:04:50 · answer #5 · answered by Como 7 · 0⤊ 0⤋
All answerers have the right idea, but it would be nice to write the answer as
f^(-1) (x) or f(inv) (x) = ....
the expression cp_exit_1... found, and Gnomon showed you how to find.
2007-01-30 05:06:11 · answer #6 · answered by Hy 7 · 0⤊ 0⤋
let F(x)=y
then y=x/2-1/2
y=1/2(x-1)
2y=x-1
so x=2y+1
2007-01-30 04:56:50 · answer #7 · answered by Pradeep Chelani 2 · 0⤊ 0⤋