A 5cm radius gold sphere has a charge of +0.110 µC. What is the potential 5.0 m away in the surrounding air?

Question

This is under ideal conditions.

Answer 1

V= q / (4 pi epsilon r)

= .11 * 10^-6 / (4 * 3.1415926535 * 8.85* 10^-12 * 5)

i dont have a calculator

u can do the math

Answer 2

The potential depends only on the total charge enclosed at 5.0m from the gold sphere. V = q/(4*π*e0*r) Plug in for q and r.