Chemistry Question?

Question

How many milliliters of .7M BaCl2 are needed to completely react with 280 ml of 0.5 M (NH4)2 CO3 ?

Answer 1

(NH4)2CO3+ Ba Cl2 --->2(NH4)Cl+Ba CO3

The reaction shows that you need as mich mole of (NH4)2CO3 as Ba Cl2

In 1liter of 0.5M, you have 0.5 mole

In 280ml = 0.28 liter you have 0.28*0.5 =0.14 mole

So you need 0.14 mole Bacl2

one liter of BaCl2 0.7m = 0.7 mole

To have 0.14 mole you need 0.14/0.7 = 0.2 liter